x²-2xy+y²分之x²-y²,其中x²+y²-2x-6y+10=0 先化简,再求值
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/16 10:21:59
![x²-2xy+y²分之x²-y²,其中x²+y²-2x-6y+10=0 先化简,再求值](/uploads/image/z/1122203-11-3.jpg?t=x%26%23178%3B-2xy%2By%26%23178%3B%E5%88%86%E4%B9%8Bx%26%23178%3B-y%26%23178%3B%2C%E5%85%B6%E4%B8%ADx%26%23178%3B%2By%26%23178%3B-2x-6y%2B10%3D0+%E5%85%88%E5%8C%96%E7%AE%80%2C%E5%86%8D%E6%B1%82%E5%80%BC)
x²-2xy+y²分之x²-y²,其中x²+y²-2x-6y+10=0 先化简,再求值
x²-2xy+y²分之x²-y²,其中x²+y²-2x-6y+10=0 先化简,再求值
x²-2xy+y²分之x²-y²,其中x²+y²-2x-6y+10=0 先化简,再求值
x²+y²-2x-6y+10=0
x²-2x+1+y²-6y+9=0
(x-1)²+(y-3)²=0
(x-1)²=0,(y-3)²=0
x=1
y=3
(x²-y²)/(x²-2xy+y²)
=(x-y)(x+y)/(x-y)²
=(x+y)/(x-y)
=(1+3)/(1-3)
=-2
楼上两层都同意,很好,看来该补补数学知识了,2次方以上的都忘光了,真不好意思!