已知数列{an}满足:an=[a(n-1)] / [3·a(n-1)+1] ,a1=1,求数列{an}的通项公式.题目请看清楚,有点乱
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/16 17:27:50
![已知数列{an}满足:an=[a(n-1)] / [3·a(n-1)+1] ,a1=1,求数列{an}的通项公式.题目请看清楚,有点乱](/uploads/image/z/1773282-66-2.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97%7Ban%7D%E6%BB%A1%E8%B6%B3%3Aan%3D%5Ba%28n-1%29%5D+%2F+%5B3%C2%B7a%28n-1%29%2B1%5D+%2Ca1%3D1%2C%E6%B1%82%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F.%E9%A2%98%E7%9B%AE%E8%AF%B7%E7%9C%8B%E6%B8%85%E6%A5%9A%2C%E6%9C%89%E7%82%B9%E4%B9%B1)
已知数列{an}满足:an=[a(n-1)] / [3·a(n-1)+1] ,a1=1,求数列{an}的通项公式.题目请看清楚,有点乱
已知数列{an}满足:an=[a(n-1)] / [3·a(n-1)+1] ,a1=1,求数列{an}的通项公式.题目请看清楚,有点乱
已知数列{an}满足:an=[a(n-1)] / [3·a(n-1)+1] ,a1=1,求数列{an}的通项公式.题目请看清楚,有点乱
两边取倒数,得到1/an-1/an-1=3,则数列{an}是一个首项为1/a1=1,公差为3的等差数列,所以1/an=3n-2,则an=1/(3n-2)
已知数列{an}满足a(n+1)=an+n,a1=1,则an=
已知数列{an}满足a(n+1)=an+lg2,a1=1,求an
周期性数列问题i已知数列{an}满足a(n+1)=2an (0
已知数列an满足1/a-an=2根号n,且an>0.求an的通项公式是数列{an}满足1/an-an=2根号n,且an>0,求an的通项公式。
已知数列an满足a1=1,a(n+1)=an/(3an+1) 求数列通项公式
已知数列an满足a1=1,a(n+1)=an/(3an+2),则an=?
已知数列an满足条件a1=-2 a(n+1)=2an/(1-an) 则an=
已知数列an满足:a1=1,an-a(n-1)=n n大于等于2 求an
已知数列{an}满足a1=33,a(n+1)-an=2n,则an/n的最小值
已知数列{an}满足a1=33,a(n+1)-an=2n,求an/n的最小值
已知数列an满足a1=100,a(n+1)-an=2n,则(an)/n的最小值为
已知数列an满足a1=2,an=a(n-1)+2n,(n≥2),求an
已知数列{an}满足a1=2,a(n+1)-an=a(n+1)*an,则a31=?
已知数列{an}满足an+1=an+n,a1等于1,则an=?
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
已知数列{an}满足a1=1,3a(n+1)+an-7
已知数列{An}满足A(n+1)=【2An (0
已知数列{an}满足a(n+1)=an+3n+2,且a1=2,求an=?