(7/x²+x)+(1/x²-x)=6/x²-1
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![(7/x²+x)+(1/x²-x)=6/x²-1](/uploads/image/z/1992762-18-2.jpg?t=%287%2Fx%26%23178%3B%2Bx%29%2B%281%2Fx%26%23178%3B-x%29%3D6%2Fx%26%23178%3B-1)
(7/x²+x)+(1/x²-x)=6/x²-1
(7/x²+x)+(1/x²-x)=6/x²-1
(7/x²+x)+(1/x²-x)=6/x²-1
(7/x²+x)+(1/x²-x)=6/x²-1
7/x(x+1)+1/x(x-1)=6/(x+1)(x-1) 两边乘x(x+1)(x-1)
7(x-1)+x+1=6x
8x-6=6x
2x=6
x=3
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