若|3x+2y-4|+|3y-2x+5|=0,求x+y的值.
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若|3x+2y-4|+|3y-2x+5|=0,求x+y的值.
若|3x+2y-4|+|3y-2x+5|=0,求x+y的值.
若|3x+2y-4|+|3y-2x+5|=0,求x+y的值.
3x+2y-4=0
3y-2x+5=0
解得x=12/13
y=-7/13
所以
x-y=19/13
∵|3x+2y-4|+|3y-2x+5|=0
∴|3x+2y-4|=0,|3y-2x+5|=0
∴3x+2y-4=0 ①
3y-2x+5=0②
∴①×2+②×3,得13y=-7
∴y=-7/13
①×3-②×2,得13x=22
∴x=22/13
∴x+y=22/13+﹙-7/13﹚=15/13
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