已知x+2y-3=0,试求x^2+4y^2+4xy+3x+6y-8的值

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已知x+2y-3=0,试求x^2+4y^2+4xy+3x+6y-8的值

已知x+2y-3=0,试求x^2+4y^2+4xy+3x+6y-8的值
已知x+2y-3=0,试求x^2+4y^2+4xy+3x+6y-8的值

已知x+2y-3=0,试求x^2+4y^2+4xy+3x+6y-8的值
x+2y-3=0,则x+2y=3
x^2+4y^2+4xy+3x+6y-8
=(x+2y)方+3(x+2y)-8
=3方+3*3-8=9+9-8=10

x+2y-3=0
x+2y=3
x^2+4y^2+4xy+3x+6y-8
=(x+2y)²+2(x+2y)-8
=(x+2y+4)(x+2y-2)
=7×1
=7

x+2y-3=0
x+2y=3
原式=(x+2y)²+3(x+2y)-8
=3²+3×3-8
=10

x+2y=3
x^2+4y^2+4xy+3x+6y-8
=(x+2y)^2+3(x+2y)-8
=9+9-8=10