X/(Y-Z)+Y/(Z-X)+Z/(X-Y)=0求证X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0通过上面求证下面^2是……的2次方X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/17 06:27:42
![X/(Y-Z)+Y/(Z-X)+Z/(X-Y)=0求证X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0通过上面求证下面^2是……的2次方X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0](/uploads/image/z/3176465-41-5.jpg?t=X%2F%28Y-Z%29%2BY%2F%28Z-X%29%2BZ%2F%28X-Y%29%3D0%E6%B1%82%E8%AF%81X%2F%28Y-Z%29%5E2%2BY%2F%28Z-X%29%5E2%2BZ%2F%28X-Y%29%5E2%3D0%E9%80%9A%E8%BF%87%E4%B8%8A%E9%9D%A2%E6%B1%82%E8%AF%81%E4%B8%8B%E9%9D%A2%5E2%E6%98%AF%E2%80%A6%E2%80%A6%E7%9A%842%E6%AC%A1%E6%96%B9X%2F%28Y-Z%29%5E2%2BY%2F%28Z-X%29%5E2%2BZ%2F%28X-Y%29%5E2%3D0)
X/(Y-Z)+Y/(Z-X)+Z/(X-Y)=0求证X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0通过上面求证下面^2是……的2次方X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0
X/(Y-Z)+Y/(Z-X)+Z/(X-Y)=0
求证
X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0
通过上面求证下面^2是……的2次方
X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0
X/(Y-Z)+Y/(Z-X)+Z/(X-Y)=0求证X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0通过上面求证下面^2是……的2次方X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0
X/(Y-Z)=-Y/(Z-X)-Z/(X-Y)
所以X/(Y-Z)^2
=-Y/(Z-X)(Y-Z)-Z/(X-Y)(Y-Z)
=[-Y(X-Y)-Z(Z-X)]/(X-Y)(Y-Z)(Z-X)
=(Y+Z-X)/(X-Y)(Z-X)
同理
Y/(Z-X)^2=-Z/(X-Y)(Z-X)-X/(Y-Z)(Z-X)
Z/(X-Y)^2=-X/(Y-Z)(X-Y)-Y/(Z-X)(X-Y)
所以
X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2
=(Y+Z-X)/(X-Y)(Z-X)-Z/(X-Y)(Z-X)-X/(Y-Z)(Z-X)-X/(Y-Z)(X-Y)-Y/(Z-X)(X-Y)
=-X/(X-Y)(Z-X)-X/(Y-Z)(Z-X)-X/(Y-Z)(X-Y)
=-X/(Z-X)[1/(X-Y)+1/(Y-Z)]-X/(Y-Z)(X-Y)
=X/(Y-Z)(X-Y)-X/(Y-Z)(X-Y)
=0
X、Y、Z的取值范围?
我不会