(x-2)分之1+(x+2)分之1+(x平方+4)分之2x+(x四次方+16)分之4x三次方
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/18 00:41:17
![(x-2)分之1+(x+2)分之1+(x平方+4)分之2x+(x四次方+16)分之4x三次方](/uploads/image/z/394182-54-2.jpg?t=%28x-2%29%E5%88%86%E4%B9%8B1%2B%28x%2B2%29%E5%88%86%E4%B9%8B1%2B%28x%E5%B9%B3%E6%96%B9%2B4%29%E5%88%86%E4%B9%8B2x%2B%28x%E5%9B%9B%E6%AC%A1%E6%96%B9%2B16%29%E5%88%86%E4%B9%8B4x%E4%B8%89%E6%AC%A1%E6%96%B9)
(x-2)分之1+(x+2)分之1+(x平方+4)分之2x+(x四次方+16)分之4x三次方
(x-2)分之1+(x+2)分之1+(x平方+4)分之2x+(x四次方+16)分之4x三次方
(x-2)分之1+(x+2)分之1+(x平方+4)分之2x+(x四次方+16)分之4x三次方
=(x+2)/(x²-4)+(x-2)/(x²-4)+(x平方+4)分之2x+(x四次方+16)分之4x三次方
=2x/(x²-4)+(x平方+4)分之2x+(x四次方+16)分之4x三次方
=[2x(x²+4)+2x(x²-4)]/(x的4次方-16)+(x四次方+16)分之4x三次方
=4x³/(x的4次方-16)+4x³/(x的4次方+16)
=8x的7次方/(x的8次方-256)
关键点是二项二项通分,合并
1/(x-2)+1/(x+2)+2x/(x²+4)+4x^3/(x^4+16)
=【(x+2)+(x-2)】/【(x+2)(x-2)】+2x/(x²+4)+4x^3/(x^4+16)
=2x/(x²-4)+2x/(x²+4)+4x^3/(x^4+16)
=【2x(x²+4)+2x(x²-4)】/【(x²-...
全部展开
1/(x-2)+1/(x+2)+2x/(x²+4)+4x^3/(x^4+16)
=【(x+2)+(x-2)】/【(x+2)(x-2)】+2x/(x²+4)+4x^3/(x^4+16)
=2x/(x²-4)+2x/(x²+4)+4x^3/(x^4+16)
=【2x(x²+4)+2x(x²-4)】/【(x²-4)(x²+4)】+4x^3/(x^4+16)
=4x^3/(x^4-16)+4x^3/(x^4+16)
=【4x^3*(x^4+16)+4x^3*(x^4-16)】/【(x^4-16)*(x^4+16)】
=8x^7/(x^8-256)
收起
1/(x-2)+1/(x+2)+2x/(x²+4)+4x³/(x^4+16)=(x+2+x-2)/(x-2)(x+2)+2x/(x²+4)+4x³/(x^4+16)(前两项先通分)
=2x/(x²-4)+2x/(x²+4)+4x³/(x^4+16)=[2x(x²+4)+2x(x²-4)]/(x...
全部展开
1/(x-2)+1/(x+2)+2x/(x²+4)+4x³/(x^4+16)=(x+2+x-2)/(x-2)(x+2)+2x/(x²+4)+4x³/(x^4+16)(前两项先通分)
=2x/(x²-4)+2x/(x²+4)+4x³/(x^4+16)=[2x(x²+4)+2x(x²-4)]/(x²-4)(x²+4)+4x³/(x^4+16)
=4x³/(x^4-16)+4x³/(x^4+16)=[4x³(x^4+16)+4x³(x^4-16)]/(x^4-16)(x^4+16)
=8x^7/(x^8-256)
希望对你有所帮助
收起