作业帮已知直角坐标系,直线AB分别与X轴,Y轴的正半轴交于点A,B且OA=OB=1.点P（a,b）在第一象限,且2ab=1,由点P向X轴,Y轴所做的垂涎PM,PN（点M,N为垂足）分别与线段AB交于点E,F,试判断三角形AOF与三角形BOE是
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已知直角坐标系,直线AB分别与X轴,Y轴的正半轴交于点A,B且OA=OB=1.点P（a,b）在第一象限,且2ab=1,由点P向X轴,Y轴所做的垂涎PM,PN（点M,N为垂足）分别与线段AB交于点E,F,试判断三角形AOF与三角形BOE是
已知直角坐标系,直线AB分别与X轴,Y轴的正半轴交于点A,B且OA=OB=1.点P（a,b）在第一象限,且2ab=1,由点P向X轴,Y轴所做的垂涎PM,PN（点M,N为垂足）分别与线段AB交于点E,F,试判断三角形AOF与三角形BOE是否一定相似,如果一定相似请加以证明；如果不一定相似或者一定不相似,请简要说明理由~
已知直角坐标系,直线AB分别与X轴,Y轴的正半轴交于点A,B且OA=OB=1.点P（a,b）在第一象限,且2ab=1,由点P向X轴,Y轴所做的垂涎PM,PN（点M,N为垂足）分别与线段AB交于点E,F,试判断三角形AOF与三角形BOE是
OM=a,AM=1-a,AE=√2(1-a)
ON=b,BN=1-b,BF=√2(1-b)
PE=PM-ME=PM-AE=b-(1-a)=a+b-1
PF=PN-NF=PN-BN=a-(1-b)=a+b-1
EF=√2(a+b-1)
BE=BF+EF=√2(1-b)+√2(a+b-1)
=√2(1-b+a+b-1)
=√2a
AF=AE+EF=√2(1-a)+√2(a+b-1)
=√2(1-a+a+b-1)
=√2b
AF/AO=√2b/1=√2*(1/2a)/1=1/√2a=BO/BE
而∠A=∠B=45
所以,三角形AOF与三角形BOE相似
Defense is the principal defense policy adviser to the President and is responsible for the formulation of general defense policy and policy related to all matters of direct concern to the Department ...
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Defense is the principal defense policy adviser to the President and is responsible for the formulation of general defense policy and policy related to all matters of direct concern to the Department of Defense, and for the execution of approved policy. Under the direction of the President, the Secretary exercises authority, direction and control over the Department of Defense. The Secretary of Defense is a member of the President's Cabinet and of the National Security Council.
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The Deputy Secretary of Defense is delegated full power and authority to act for the Secretary of Defense and exercise the powers of the Secretary on any and all matters for which the Secretary is authorized to act pursuant to law.
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