作业帮化简 [a^(1/2)-b^(1/2)] / [a^(1/2)+b^(1/2)]+[a^(1/2)+b^(1/2)]/ [a^(1/2)-b^(1/2)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/05 03:15:14
![化简 [a^(1/2)-b^(1/2)] / [a^(1/2)+b^(1/2)]+[a^(1/2)+b^(1/2)]/ [a^(1/2)-b^(1/2)]](/uploads/image/z/7103473-25-3.jpg?t=%E5%8C%96%E7%AE%80+%5Ba%5E%281%2F2%29-b%5E%281%2F2%29%5D+%2F+%5Ba%5E%281%2F2%29%2Bb%5E%281%2F2%29%5D%2B%5Ba%5E%281%2F2%29%2Bb%5E%281%2F2%29%5D%2F+%5Ba%5E%281%2F2%29-b%5E%281%2F2%29%5D)
化简 [a^(1/2)-b^(1/2)] / [a^(1/2)+b^(1/2)]+[a^(1/2)+b^(1/2)]/ [a^(1/2)-b^(1/2)]
化简 [a^(1/2)-b^(1/2)] / [a^(1/2)+b^(1/2)]+[a^(1/2)+b^(1/2)]/ [a^(1/2)-b^(1/2)]
化简 [a^(1/2)-b^(1/2)] / [a^(1/2)+b^(1/2)]+[a^(1/2)+b^(1/2)]/ [a^(1/2)-b^(1/2)]
通分
原式={[a^(1/2)-b^(1/2)]^2+[a^(1/2)+b^(1/2)]^2/[a^(1/2)+b^(1/2)] [a^(1/2)-b^(1/2)]
=[a-2a^(1/2)b^(1/2)+b+a+2a^(1/2)b^(1/2)+b]/(a-b)
=(2a+2b)/(a-b)