a+1的绝对值与2a+b的绝对值互为相反数,求整式3(a-b)-5(a-b)²+3(a+b)+(a-b)²····a+1的绝对值与2a+b的绝对值互为相反数,求整式 3(a-b)-5(a-b)²+3(a+b)+(a-b)²-7(a+b)²-3(a+b)
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![a+1的绝对值与2a+b的绝对值互为相反数,求整式3(a-b)-5(a-b)²+3(a+b)+(a-b)²····a+1的绝对值与2a+b的绝对值互为相反数,求整式 3(a-b)-5(a-b)²+3(a+b)+(a-b)²-7(a+b)²-3(a+b)](/uploads/image/z/765310-22-0.jpg?t=a%2B1%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%E4%B8%8E2a%2Bb%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E6%B1%82%E6%95%B4%E5%BC%8F3%EF%BC%88a-b%EF%BC%89-5%28a-b%29%26%23178%3B%2B3%28a%2Bb%29%2B%28a-b%29%26%23178%3B%C2%B7%C2%B7%C2%B7%C2%B7a%2B1%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%E4%B8%8E2a%2Bb%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E6%B1%82%E6%95%B4%E5%BC%8F+3%EF%BC%88a-b%EF%BC%89-5%28a-b%29%26%23178%3B%2B3%28a%2Bb%29%2B%28a-b%29%26%23178%3B-7%28a%2Bb%29%26%23178%3B-3%EF%BC%88a%2Bb%EF%BC%89)
a+1的绝对值与2a+b的绝对值互为相反数,求整式3(a-b)-5(a-b)²+3(a+b)+(a-b)²····a+1的绝对值与2a+b的绝对值互为相反数,求整式 3(a-b)-5(a-b)²+3(a+b)+(a-b)²-7(a+b)²-3(a+b)
a+1的绝对值与2a+b的绝对值互为相反数,求整式3(a-b)-5(a-b)²+3(a+b)+(a-b)²····
a+1的绝对值与2a+b的绝对值互为相反数,求整式 3(a-b)-5(a-b)²+3(a+b)+(a-b)²-7(a+b)²-3(a+b)
a+1的绝对值与2a+b的绝对值互为相反数,求整式3(a-b)-5(a-b)²+3(a+b)+(a-b)²····a+1的绝对值与2a+b的绝对值互为相反数,求整式 3(a-b)-5(a-b)²+3(a+b)+(a-b)²-7(a+b)²-3(a+b)
答:
相反数之和为0,所以:
|a+1|+|2a+b|=0
两个绝对值同时为0时和为0
所以:
a+1=0
2a+b=0
解得:a=-1,b=2
所以:
3(a-b)-5(a-b)²+3(a+b)+(a-b)²-7(a+b)²-3(a+b)
=3(a-b)-4(a-b)²-7(a+b)²
=3×(-3)-4×(-3)²-7×(-1+2)²
=-9-36-7
=-52
1.已知|a+1|与|2a+b|互为相反数
则|a+1|+|2a+b|=0
则a=-1 b=2
所以3(a-b)-5(a-b)²+3(a+b)+(a-b)²-7(a+b)²-3(a+b)
=3(a-b)-4(a-b)²-7(a+b)²
=3(-1-2)-4(-1-2)²-7(-1+2)²
=-9-36-7
=-52
绝对值永远大于等于0,所以绝对值a+1=0 2a+b=0
所以a=-1 b=2.剩下的自己算吧。。。
望采纳哈。。