作业帮[(x^2-4y^2)(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/03 16:33:23
![[(x^2-4y^2)(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]](/uploads/image/z/8684650-10-0.jpg?t=%5B%28x%5E2-4y%5E2%29%28x%2By%29%5D%2F%28x%5E2-2xy%29%2F%5B%28x%5E2%2Bxy-2y%5E2%29%5C%28x%5E2-y%5E2%29%5D)
[(x^2-4y^2)(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
[(x^2-4y^2)(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
[(x^2-4y^2)(x+y)]/(x^2-2xy)/[(x^2+xy-2y^2)\(x^2-y^2)]
(x^2-4y^2)(x+y)=(x+2y)(x-2y)（x+y）
(x^2+xy-2y^2)=(x+2y)(x-y)
x^2-y^2=(x+y)(x-y)
先计算分母部分=(x+2y)/(x+y)
原式=[(x+2y)(x-2y)(x+y)]/[(x+2y)/(x+y)]
=(x-2y)(x+y)^2