1.(1)x-2=x(x-2)(2)(3x-4) ^2=(4x-3)^22.已知a,b,c均为实,且√(a-1)+|b+1|+(c+3)^2=0,求方程ax^2+bx+c=03.已知关于x的方程x^2-(k+1)x+k+2=0的两个实数根的平方和等于6,求k的值.4.菱形ABCD的边长是5,两条对角线交于点O,
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![1.(1)x-2=x(x-2)(2)(3x-4) ^2=(4x-3)^22.已知a,b,c均为实,且√(a-1)+|b+1|+(c+3)^2=0,求方程ax^2+bx+c=03.已知关于x的方程x^2-(k+1)x+k+2=0的两个实数根的平方和等于6,求k的值.4.菱形ABCD的边长是5,两条对角线交于点O,](/uploads/image/z/8837395-43-5.jpg?t=1.%281%29x-2%3Dx%28x-2%29%282%29%283x-4%29+%5E2%3D%284x-3%29%5E22.%E5%B7%B2%E7%9F%A5a%2Cb%2Cc%E5%9D%87%E4%B8%BA%E5%AE%9E%2C%E4%B8%94%E2%88%9A%28a-1%29%2B%7Cb%2B1%7C%2B%28c%2B3%29%5E2%3D0%2C%E6%B1%82%E6%96%B9%E7%A8%8Bax%5E2%2Bbx%2Bc%3D03.%E5%B7%B2%E7%9F%A5%E5%85%B3%E4%BA%8Ex%E7%9A%84%E6%96%B9%E7%A8%8Bx%5E2-%28k%2B1%29x%2Bk%2B2%3D0%E7%9A%84%E4%B8%A4%E4%B8%AA%E5%AE%9E%E6%95%B0%E6%A0%B9%E7%9A%84%E5%B9%B3%E6%96%B9%E5%92%8C%E7%AD%89%E4%BA%8E6%2C%E6%B1%82k%E7%9A%84%E5%80%BC.4.%E8%8F%B1%E5%BD%A2ABCD%E7%9A%84%E8%BE%B9%E9%95%BF%E6%98%AF5%2C%E4%B8%A4%E6%9D%A1%E5%AF%B9%E8%A7%92%E7%BA%BF%E4%BA%A4%E4%BA%8E%E7%82%B9O%2C)
1.(1)x-2=x(x-2)(2)(3x-4) ^2=(4x-3)^22.已知a,b,c均为实,且√(a-1)+|b+1|+(c+3)^2=0,求方程ax^2+bx+c=03.已知关于x的方程x^2-(k+1)x+k+2=0的两个实数根的平方和等于6,求k的值.4.菱形ABCD的边长是5,两条对角线交于点O,
1.(1)x-2=x(x-2)
(2)(3x-4) ^2=(4x-3)^2
2.已知a,b,c均为实,且√(a-1)+|b+1|+(c+3)^2=0,求方程ax^2+bx+c=0
3.已知关于x的方程x^2-(k+1)x+k+2=0的两个实数根的平方和等于6,求k的值.
4.菱形ABCD的边长是5,两条对角线交于点O,切AO、BO的长(AO
1.(1)x-2=x(x-2)(2)(3x-4) ^2=(4x-3)^22.已知a,b,c均为实,且√(a-1)+|b+1|+(c+3)^2=0,求方程ax^2+bx+c=03.已知关于x的方程x^2-(k+1)x+k+2=0的两个实数根的平方和等于6,求k的值.4.菱形ABCD的边长是5,两条对角线交于点O,
1:X-2=X^2-2X
X^2-3X+2=0
(X-1)*(X-2)=0
X=1或=2因为X-2不等于0
所以X=1
9X^2-24X+16=16X^2-24X+9
7X^2=7
x^2=1
x=1或X=-1
2:因abc为实数,√(a-1)+|b+1|+(c+3)^2=0知√(a-1)=0;|b+1|=0; (c+3)^2=0得a=1,b=-1,c=-3.则方程ax^2+bx+c=0为x^2-x-3=0
该方程无解
3:设方程x^2-(k+1)x+k+2=0的两个实数根为x1和x2.x1+x2=-(k+1) x1*x2=k+2.x1^2+x2^2=6变形为(X1+X2)^2-2*x1x2=6
即(k+1)^2-2k-4=6
解得k=3或-3
4:由条件:菱形ABCD,边长为5,AO,BO 是对角线一半,且AO
1.X=1
(2).3X-4=4x-3
x=-1
2.√是什么?
3.-2ac/b -2*(c+3)/-(k+1)