cos5π/12-根3sin5π/12过程

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cos5π/12-根3sin5π/12过程
cos5π/12-根3sin5π/12
过程

cos5π/12-根3sin5π/12过程
这个其实直接用辅助角公式就可以求出来了：
acosx-bsinx=√(a²+b²)*cos(x+φ) (其中tanφ=b/a)
cos5π/12-√3sin5π/12
=2cos(5π/12+π/3)
=2cos3π/4
=-√2

1 ,cos5π/12·sinπ/12 =cos(π/4+π/6)*sin(π/4-π/6) =((1-tanαtanβ)=(tanα+tanβ) 1+4/3tanβ=-4/3tanβ ,tanβ=-

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