2lg 5+lg2*lg50=1

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2lg 5+lg2*lg50=1
2
lg 5+lg2*lg50=1

2lg 5+lg2*lg50=1
=lg5*lg5+lg2(lg5+lg10)
=lg5*lg5+lg2(lg5+1)
=lg5*lg5+lg5*lg2+lg2
=lg5(lg5+lg2)+lg2
=lg5+lg2
=1

首先你要记得公式: a^[logc(b)]=b^[logc(a)]
这道题是这样的=lg5*lg5+lg2(lg5+lg10)
=lg5*lg5+lg2(lg5+1)
=lg5*lg5+lg5*lg2+lg2
=lg5(lg5+lg2)+lg2
=lg5+lg2
=1

lg5*lg5+lg2(lg5+lg10)
=lg5*lg5+lg2(lg5+1)
=lg5*lg5+lg5*lg2+lg2
=lg5(lg5+lg2)+lg2
=lg5+lg2
=1

2lg 5+lg2*lg50=1 lg25+lg2*lg50+lg^2 2=? lg50+lg2*lg5+lg²2=? (lg^2)^2+lg^2*lg^50+lg^25=?(lg2)^2+lg2*lg50+lg25=? 计算：｜lg2-lg^2(5)｜+lg2·lg50+√(lg5-1)^2 lg25+lg2*lg50+(lg2)^2+1=? lg的平方5+lg2 ×lg50 计算lg的平方5+lg2*lg50 lg25+lg2*lg50+lg平方2 1g^2+lg2*lg50=? lg2.lg50=lg2.{lg(2.lg50怎么推出lg(2.25)的? ｜lg2—lg平方5｜+ lg2*lg50+ 根号（lg5-1）平方求（lg50)^2+lg2*lg(50)^2+(lg2)^2 求值：lg25 lg2*lg50 (lg2)^2求值：1 lg25+lg2*lg50+(lg2)^2 2 已知集合 {x,y,lg(xy)}={0,y,绝对值x},求log8（x^2+y^2)的值 (lg5)^2+lg2×lg50=? (lg5)^2 + (lg2)*(lg50)= (lg5)^2+lg2*lg50= lg25+lg2·lg50+(lg2)^2=?