极限 1+X/1-X的cotx次方 x到0x->0时,ln [1+ 2x/(1-x)] 2x/(1-x) 2x ,e ^ lim(x->0) cotx * ln [1+ 2x/(1-x)]这两步不懂

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/07 06:14:54
极限 1+X/1-X的cotx次方 x到0x->0时,ln [1+ 2x/(1-x)] 2x/(1-x) 2x ,e ^ lim(x->0) cotx * ln [1+ 2x/(1-x)]这两步不懂

极限 1+X/1-X的cotx次方 x到0x->0时,ln [1+ 2x/(1-x)] 2x/(1-x) 2x ,e ^ lim(x->0) cotx * ln [1+ 2x/(1-x)]这两步不懂
极限 1+X/1-X的cotx次方 x到0
x->0时,ln [1+ 2x/(1-x)] 2x/(1-x) 2x ,e ^ lim(x->0) cotx * ln [1+ 2x/(1-x)]这两步不懂

极限 1+X/1-X的cotx次方 x到0x->0时,ln [1+ 2x/(1-x)] 2x/(1-x) 2x ,e ^ lim(x->0) cotx * ln [1+ 2x/(1-x)]这两步不懂
当x->0时,ln [1+ 2x/(1-x)] 2x/(1-x) 2x ,
lim(x->0) [1+ 2x/(1-x)] ^ (cotx)
= e ^ lim(x->0) cotx * ln [1+ 2x/(1-x)]
= e ^ lim(x->0) ln [1+ 2x/(1-x)] / tanx
= e ^ lim(x->0) 2 x / tanx
= e^2