[√a+(b-√ab)/(√a+√b)]/[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]=

化简：(√a²+a√b)/(ab-b²)-(a+√ab+b)/(a√a-b√b) 已知:a+b=-8,ab=12,b*√(b/a)+a*√(a/b) (a- √ab -2b)分之(a - 2√ab) +(a√a + b√b)分之(a√b -b√a +b√b) 化简 初三高一数学题一道.[√a+(b-√ab)/(√a+√b)]÷[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab] [√a+(b-√ab)/(√a+√b)]/[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]= 计算[(√ab ) －ab/(a+√ab)]÷(√ab)－b/a－b (√ab-ab/a+√ab)×√ab-b/a-b 数学题(a√b-b√a)/√ab化简 a b为R+ a+b+√ab的最小值 计算题[a+2√(ab) +b]/(a-b)-[a+b-2√(ab)]/(√a-√b) 已知a>b>0,求证：（a-b)^2/8a < (a+b)/2 -√ab < (a-b)^2/8b 化简[√ab-ab/(a+√ab)]÷(√ab-a)/(a-b) 谁帮我化解下面两题急![(a√a)+(a√b)]/[ab-b^2]-[(a+√ab)+b]/[(a√a)-(b√b)] >=a+b>=2√ab, 推导a+b>=2√ab 已知a>0,b>0,求证√a+√b+√ab≤a+b+1 √a(√a+√b)=3√b(√a+√b)求2a+3b+√ab分之a-b+√ab的值 已知a+b=5,ab=6,求√b/a+a/b