关于MATLAB的求解记d=(88,53,18,6,7)b0=(71,30,7,4,1)b1=(27,18,9,3,3)b2=(34,17,0,0,1)b3=(37,13,7,4,0) b4=(18,12,6,2,2)b5=(33,28,5,0,5)b6=(17,23,11,2,6)求解k(i,j)k(0,j)*b(0)+k(1,j)*b(1)+k(2,j)*b(2)+k
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/18 02:40:49
![关于MATLAB的求解记d=(88,53,18,6,7)b0=(71,30,7,4,1)b1=(27,18,9,3,3)b2=(34,17,0,0,1)b3=(37,13,7,4,0) b4=(18,12,6,2,2)b5=(33,28,5,0,5)b6=(17,23,11,2,6)求解k(i,j)k(0,j)*b(0)+k(1,j)*b(1)+k(2,j)*b(2)+k](/uploads/image/z/7823147-59-7.jpg?t=%E5%85%B3%E4%BA%8EMATLAB%E7%9A%84%E6%B1%82%E8%A7%A3%E8%AE%B0d%3D%2888%2C53%2C18%2C6%2C7%29b0%3D%2871%2C30%2C7%2C4%2C1%29b1%3D%2827%2C18%2C9%2C3%2C3%29b2%3D%2834%2C17%2C0%2C0%2C1%29b3%3D%2837%2C13%2C7%2C4%2C0%29++++++++++++++++++++++++++++++++++++++++++++++++b4%3D%2818%2C12%2C6%2C2%2C2%29b5%3D%2833%2C28%2C5%2C0%2C5%29b6%3D%2817%2C23%2C11%2C2%2C6%29%E6%B1%82%E8%A7%A3k%28i%2Cj%29k%280%2Cj%29%2Ab%280%29%2Bk%281%2Cj%29%2Ab%281%29%2Bk%282%2Cj%29%2Ab%282%29%2Bk)
关于MATLAB的求解记d=(88,53,18,6,7)b0=(71,30,7,4,1)b1=(27,18,9,3,3)b2=(34,17,0,0,1)b3=(37,13,7,4,0) b4=(18,12,6,2,2)b5=(33,28,5,0,5)b6=(17,23,11,2,6)求解k(i,j)k(0,j)*b(0)+k(1,j)*b(1)+k(2,j)*b(2)+k
关于MATLAB的求解
记d=(88,53,18,6,7)
b0=(71,30,7,4,1)
b1=(27,18,9,3,3)
b2=(34,17,0,0,1)
b3=(37,13,7,4,0)
b4=(18,12,6,2,2)
b5=(33,28,5,0,5)
b6=(17,23,11,2,6)
求解k(i,j)
k(0,j)*b(0)+k(1,j)*b(1)+k(2,j)*b(2)+k(3,j)*b(3)+k(4,j)*b(4)+k(5,j)*b(5)+k(6,j)*b(6)=d
关于MATLAB的求解记d=(88,53,18,6,7)b0=(71,30,7,4,1)b1=(27,18,9,3,3)b2=(34,17,0,0,1)b3=(37,13,7,4,0) b4=(18,12,6,2,2)b5=(33,28,5,0,5)b6=(17,23,11,2,6)求解k(i,j)k(0,j)*b(0)+k(1,j)*b(1)+k(2,j)*b(2)+k
d=[88,53,18,6,7]
b0=[71,30,7,4,1]
b1=[27,18,9,3,3]
b2=[34,17,0,0,1]
b3=[37,13,7,4,0]
b4=[18,12,6,2,2]
b5=[33,28,5,0,5]
b6=[17,23,11,2,6]
result=d/[b0;b1;b2;b3;b4;b5;b6]
这样的结果是一组解,根据最小二乘原理得到的.
楼主的问题似乎是所有的线性组合,这样是出不来的吧?