(sqrt(cos(x))*cos(200x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01,sqrt(9-x^2),-sqrt(9

(sqrt(cos(x))*cos(200x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01,sqrt(9-x^2),-sqrt(9 lim(cos(sqrt(x)))^1/x y=sin x + sqrt(3)cos x的周期 sqrt(abs(cos(x/180)))和sqrt(fabscos((x/180))))有什么不同rt 1-sqrt(3)=2cos²x+sqrt(3)sin2x则x等于多少 Sqrt[2] * { Sin( x + π/4 ) * cos[ π/4 ] + Cos[ x + π/4] * sin[ π/4 ] = Sqrt[2] *sin (x + π/2)我这一步看不懂.. 设函数f(x)=cos(sqrt(3)*x+φ)(0 求函数cos^2x+sqrt(3)sin2x+a的单调递增区间. matlab求解下列方程的解,画出（x,y）的曲线图(2*x-1200*sin(t)-400)^2+(2*y+1200*cos(t)-1200-sqrt(1280000))^2=1440000;(2*x-2400*sin(t))^2+(2*y+2400*cos(t)-2400-2*sqrt(1280000))^2=160000+(l-sqrt(1280000))^2;其中给t一个范围t=-20/180*p 用matlab求解超越方程我的方程是-0.17*cos(5.6*sqrt(a))*cos(0.47*sqrt(a))+0.163*sin(5.6*sqrt(a))*sin(0.47*sqrt(a))+0.119*sqrt(a)*sin(5.6*sqrt(a))*cos(0.47*sqrt(a))+0.104*sqrt(a)*cos(5.6*sqrt(a))*sin(0.47*sqrt(a))-(0.06*cos(5.6*sqrt(a))*sin(0 高数极限题,x->0的极限?f=x^2/(sqrt(1+x*sin(x))-sqrt(cos(x))); 4/3 求工程! 求高手解答用Matlab 如何在matlab编程求这个方程组的解啊?已知a,b,c方程组72.8*(1+cos(a)）=2*(SQRT(x*21.8)+SQRT(25.5*y)+SQRT(25.5*z))50.8*(1+cos(b))=2*SQRT(x*50.8)48*(1+cos(c))=2*(SQRT(x*29)+SQRT(47*y)+SQRT(1.92*z))求x,y,z假设 cos x cos x 有关mathematica Solve[x - ArcSin[Sin[x + 0.1364]/Sqrt[(1880/178)^2 + 1 - 3760/178*Cos[x + 0.1364]]] - ArcCos[(1880/178*(2*Cos[x] - Cos[x + 0.1364] - Cos[2*x]))/Sqrt[(1880/178)^2 + 1 - 3760/178*Cos[x + 0.1364]]] == -89.8635,x]我这个公式怎么 matlab中 sqrt(1+(cos（x）)^2)的积分>> fun=inline('sqrt(1+(cos（x）)^2)')fun =Inline function:fun(cos,x) = sqrt(1+(cos（x）)^2)>> [R,k,T]=Romberg(fun,realmin,4,1e-6)Error using ==> inline.subsrefNot enough inputs to inline function.Error in a*sin(x)+b*cos(x)化简 其结果是 sqrt(a^2+b^2)*sin(x+arctan(a/b))吗那转换为cos是什么呢 在matlab中输入表达式的问题x=0:0.01:8;表达式为：(sqrt(16*cos(x)*cos(x)+240)-4*cos(x))/2时出现错误：? Error using ==> mtimesInner matrix dimensions must agree.表达式为：(sqrt(16*cos(x)^2+240)-4*cos(x))/2时,出现错误：? Er