sqrt(abs(cos(x/180)))和sqrt(fabscos((x/180))))有什么不同rt

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/12 22:09:07
sqrt(abs(cos(x/180)))和sqrt(fabscos((x/180))))有什么不同rt

sqrt(abs(cos(x/180)))和sqrt(fabscos((x/180))))有什么不同rt
sqrt(abs(cos(x/180)))和sqrt(fabscos((x/180))))有什么不同
rt

sqrt(abs(cos(x/180)))和sqrt(fabscos((x/180))))有什么不同rt
sqrt(fabs(cos(x/180))))是取浮点运算.
sqrt(abs(cos(x/180))))是整形.
自己可以写个小程序,来证明FABS和ABS的区别

sqrt(abs(cos(x/180)))和sqrt(fabscos((x/180))))有什么不同rt (sqrt(cos(x))*cos(200x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01,sqrt(9-x^2),-sqrt(9 math.cos(75*3.14/180)+math.sqrt(x+math.exp(3))/math.Abs(x-y)-math.log(3x)哪里错了. SIGN(X)*SQRT(ABS(X))怎么做 Error using ==> mtimes Inner matrix dimensions must agree 用matlab求解时出现错误x=0:1:12;a=sqrt(10.08+0.5*sqrt(406.43+31.7*x.^2));b=sqrt(-10.08+0.5*sqrt(406.43+31.7*x.^2));c=1./(2*cos(0.115*sqrt(5.63i*x+20.16))); y=0;f=499800*(abs(c)).^2*x*(e lim(cos(sqrt(x)))^1/x sin,cos,tan,asin,acos,atan,sinh,cosh,sqrt,abs,min,max y=sin x + sqrt(3)cos x的周期 1-sqrt(3)=2cos²x+sqrt(3)sin2x则x等于多少 sin,cos,tan,asin,acos,atan,sinh,cosh,sqrt,abs,min,max 这些函数是什么意思代表什么 如何用matlab计算下列函数?我将下面这个输入matlab中后,[x,y] = solve('72.8*(1+cos(120.1/180*pi)) = 2*sqrt(21.8*x)+2*sqrt(51*y)','48.0*(1+cos(81.4/180*pi)) = 2*sqrt(29.0*x)+2*sqrt(19.0*y)'),提示我:x =[ empty sym ]y =[]请问怎么 新手求教matlab fmincon函数的问题 等待中.求在0<α<=π/2;0<β<=π/2,θ=0时的最小值,function f=myfirstfun(x)f=abs(1/((sqrt(sin(x(1)/180*pi)*sin(x(2)/180*pi)))*(cos((x(1)+x(2))/180*pi))));x0=[1;1];[x,fval] = fmincon('my matlab编程问题z(find(z>0))=nan作何解释a1=-0.05;%微凸体1的参数y=a*x^2+b*y^2+cb1=-0.2;c1=5;x=linspace(-sqrt(abs(c1/a1)),sqrt(abs(c1/a1)),100);y=linspace(-sqrt(abs(c1/b1)),sqrt(abs(c1/b1)),100);[x,y]=meshgrid(linspace(-sqrt(abs(c1/a1)),sqr matlab中function和end问题,错误提示This statement is not inside any function.(6行代码)function RC = reflect_coeff( ZL,Z0,f )RC = 0.5*abs(ZL-Z0)/sqrt(ZL*Z0)*abs(cos(f*pi/2));endx=0:0.1:5;a=reflect_coeff(100,50,x);plot(x,a,'b-')---------- matlab中abs(1,sin(x))*cos(x)是什么意思 proe5.0绝对值函数abs()x=20*(t-0.5)+5*cos(t*540)y=10*sin(t*540)z=abs(t-0.5)总是没办法输出曲线,有谁清楚为什么?后来发现一个方法也可以实现绝对值即z=sqrt((t-0.5)^2) 表达式sqrt(abs(-100)*sqr(round(5.8))) 写出函数f(x) = sqrt(a^2 - x^2)/[abs(x + a) + a]为奇函数的充要条件并证明.