设函数f(x)=x^3-3ax+b(a不等于0)若函数在点(2,f(2))处与直线y=8相切 求a,b的值
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![设函数f(x)=x^3-3ax+b(a不等于0)若函数在点(2,f(2))处与直线y=8相切 求a,b的值](/uploads/image/z/4321336-40-6.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%EF%BC%88x%29%3Dx%5E3-3ax%2Bb%28a%E4%B8%8D%E7%AD%89%E4%BA%8E0%EF%BC%89%E8%8B%A5%E5%87%BD%E6%95%B0%E5%9C%A8%E7%82%B9%282%2Cf%282%29%29%E5%A4%84%E4%B8%8E%E7%9B%B4%E7%BA%BFy%3D8%E7%9B%B8%E5%88%87+%E6%B1%82a%2Cb%E7%9A%84%E5%80%BC)
设函数f(x)=x^3-3ax+b(a不等于0)若函数在点(2,f(2))处与直线y=8相切 求a,b的值
设函数f(x)=x^3-3ax+b(a不等于0)
若函数在点(2,f(2))处与直线y=8相切 求a,b的值
设函数f(x)=x^3-3ax+b(a不等于0)若函数在点(2,f(2))处与直线y=8相切 求a,b的值
f(x)=x^3-3ax+b
f'(x)=3x^2-3a
若函数在点(2,f(2))处与直线y=8相切
经过(2,8)
f'(2)=12-3a=0
a=4
8=8-12*2+b
b=24
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